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xmlhttprequest post
mainfo для xmlhttprequest post: видео, блоги, определения, информация, загрузка, ссылки, Вопросы и ответы
xmlhttprequest post


 
 
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Википедия

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Ссылки

 
 
Блоги

http://huangdekai1.blog.163.com/blog/static/30571416200872812448179
在请求和响应中使用XML (by: 梦想

在网页中编写代码与服务器通信时,无论使用Ajax还是普通的表单<b>POST</b>,甚至超链接,打交道的都是HTTP。 既然浏览器和服务器之间的所有Web通信都&

http://cake--php.blogspot.com/2008/08/re-jquery-json_27.html
Re: JQuery + JSON (by: XL)

X-Requested-With <b>XMLHttpRequest</b> u0026gt; Referer http://localhost/mkb/ u0026gt; Cookie CAKEPHPu003d49d5o6b48nf83q8q12lle0pt41; u0026gt; CAKEPHPu003d02sc14jclvued57ghlaprj0j11 u0026gt; u0026gt; u0026gt; Here's the View in the app: u0026gt; u0026lt;?php u0026gt; echo $javascript-u0026gt;object($<b>post</b>); <b>...</b>

 
Видео

 
 
Загрузки

 
Определение

No definitions found for xmlhttprequest post.<br /><hr width="80%" />
 
Вопросы и ответы

How to connect to any website using AJAX? I am getting permission denied to call method xmlhttpreque
I do not need to post any data to the website, I'd just like to read from it. I'm trying to write my own RSS reader but I can not seem to get around this error. Thanks.

XMLHttpRequest is bound by the "same origin security policy", and can only make connections to the same domain that the web page is hosted on. If this restriction did not exist, any web site you visit would be able to steal your entire online life (webmail, passwords, etc). The way around it is to set up a proxy on a server you control, have that call the desired pages and forward them to you.